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Chemistry & Materials Science

Clausius-Clapeyron Calculator

Predict the new vapor pressure of a liquid at a specific temperature using the Clausius-Clapeyron equation and its enthalpy of vaporization.

Torr
K
K
kJ/mol
Final Vapor Pressure (P₂)
361.795 Torr
Vapor Pressure Ratio (P₂/P₁)0.4760

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The Vapor Pressure Curve

We know that if you heat a liquid up, it evaporates faster (its vapor pressure increases). But this relationship is not a simple straight line; it is a steep, dramatic exponential curve.

The Clausius-Clapeyron Equation allows us to trace this exact curve. If we know the vapor pressure of a liquid at one temperature, we can use this massive equation to perfectly predict what its vapor pressure will be at any other temperature in the universe.

The Heat of Vaporization

The entire equation revolves around ΔHvap\Delta H_{vap} (The Enthalpy of Vaporization). This is the exact amount of thermal energy required to physically tear the molecules of a liquid apart so they can become a gas.

  • Water has a very high ΔHvap\Delta H_{vap} because its molecules are locked together tightly by Hydrogen Bonds. It takes massive heat to force it to evaporate.
  • Rubbing alcohol has a low ΔHvap\Delta H_{vap}, which is why it evaporates rapidly off your skin, absorbing your body heat and feeling cold.

The Two-Point Equation

ln(P2P1)=ΔHvapR(1T21T1)\begin{aligned} \ln\left(\frac{P_2}{P_1}\right) = -\frac{\Delta H_{vap}}{R} \left( \frac{1}{T_2} - \frac{1}{T_1} \right) \end{aligned}

Where:
P1,P2P_1, P_2=
Vapor Pressures
T1,T2T_1, T_2=
Temperatures (Kelvin)
ΔHvap\Delta H_{vap}=
Enthalpy of Vaporization
R=
Ideal Gas Constant (8.314 J/mol·K)

Note: The temperatures must always be strictly in Kelvin, and the Enthalpy is typically converted from kJ to standard Joules to match the 8.3148.314 Gas Constant.

Frequently Asked Questions

Absolutely! The normal boiling point of any liquid is simply the exact temperature (T2T_2) where its vapor pressure (P2P_2) reaches exactly 1 atm (760 Torr). If you know ΔHvap\Delta H_{vap}, you can algebraially solve for that exact boiling temperature.

Because the relationship between temperature and pressure is exponential, governed by the Boltzmann distribution of kinetic energy. The natural log is the mathematical tool used to 'flatten' an exponential curve into a straight line that we can calculate.

Yes, there is a nearly identical version for Sublimation (a solid turning directly into a gas, like Dry Ice). You simply replace the Enthalpy of Vaporization with the Enthalpy of Sublimation (ΔHsub\Delta H_{sub}).