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Chemistry & Materials Science

Titration Calculator

Determine the unknown concentration of an analyte from a titration using the exact volume and concentration of the standardized titrant.

M
mL
mL
NaN

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Determine the unknown concentration of an analyte using the volume of a standardized titrant. This calculator handles the stoichiometry of acid-base and redox titrations instantly, ensuring precise analytical results.

The Titration Equation

At the equivalence point of a titration, the stoichiometric moles of titrant added perfectly neutralize or react with the moles of the analyte. By knowing the exact volumes and the titrant's molarity, you can isolate the analyte's concentration.

Ma=Mt×Vt×naVa×nt\begin{aligned} M_a = \frac{M_t \times V_t \times n_a}{V_a \times n_t} \end{aligned}

Where:
MaM_a=
Concentration of Analyte (M)
MtM_t=
Concentration of Titrant (M)
VtV_t=
Volume of Titrant Added (mL)
VaV_a=
Initial Volume of Analyte (mL)
nan_a=
Moles of Analyte (from balanced equation)
ntn_t=
Moles of Titrant (from balanced equation)

Stoichiometric Ratios Matter

Do not forget to input the stoichiometric moles from your balanced chemical equation! If you are titrating sulfuric acid (H2SO4H_2SO_4) with sodium hydroxide (NaOHNaOH), it requires 2 moles of NaOHNaOH for every 1 mole of acid.

Frequently Asked Questions

The equivalence point is the exact moment in a titration when the amount of added titrant chemically neutralizes the analyte according to the stoichiometric ratio.

The equivalence point is the theoretical, mathematical completion of the reaction. The endpoint is the physical moment you observe a color change from your indicator. Ideally, they happen at the exact same volume.

The titrant is the solution of known concentration in the buret. The analyte is the solution of unknown concentration in the flask below.

Because not all acids and bases react in a 1:1 ratio. For example, neutralizing a diprotic acid like H2SO4H_2SO_4 requires twice as many moles of a monoprotic base like NaOHNaOH.

No. As long as both the titrant volume and analyte volume are entered in the same unit (e.g., both in mL), the ratio cancels out and the calculation remains perfectly accurate.

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