Physics & Mechanics

Acoustic Resonance Calculator

Calculate the resonant frequencies of an open or closed pipe. Determine the fundamental frequency and harmonics based on tube length and the speed of sound.

m
m/s
Resonant Frequency (f_n)
171.5

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The Physics of Musical Instruments

Acoustic resonance is the phenomenon where an acoustic system amplifies sound waves whose frequency matches one of its own natural frequencies of vibration (its resonance frequencies).

This is the exact principle behind every wind instrument, from a tiny flute to a massive church organ. By blowing air across an opening, you create a spectrum of white noise. The physical shape of the pipe "selects" and amplifies the specific frequencies that perfectly fit inside it as standing waves.

Open vs. Closed Pipes

The boundaries of the pipe determine how the standing waves form:

  • Open Both Ends (Flutes, Open Organ Pipes): The wave has an "antinode" (maximum vibration) at both ends. The fundamental frequency (1st harmonic) fits half a wavelength inside the pipe.
  • Closed One End (Clarinets, Stopped Organ Pipes): The wave has a "node" (zero vibration) at the closed end and an antinode at the open end. The fundamental frequency fits only a quarter of a wavelength inside the pipe, making the sound exactly one octave lower than an open pipe of the same length.

The Formula

fn=nv2L(Open)orfn=nv4L(Closed)\scriptsize \begin{aligned} f_n = \frac{n \cdot v}{2 \cdot L} \quad \text{(Open)} \quad \text{or} \quad f_n = \frac{n \cdot v}{4 \cdot L} \quad \text{(Closed)} \end{aligned}

Where:
fnf_n=
Resonant Frequency of the nth harmonic
n=
Harmonic Number (1, 2, 3... for open; 1, 3, 5... for closed)
v=
Speed of Sound
L=
Length of the pipe

Example Calculation

You have a pipe that is $1 , \text{meter}$ long, open at both ends. The speed of sound is $343 , \text{m/s}$. Find the fundamental frequency ($n=1$).

  1. Multiply n by Velocity: $1 \times 343 = 343$.
  2. Multiply Length by 2: $2 \times 1 = 2$.
  3. Divide: $343 / 2 = 171.5 , \text{Hz}$.

The pipe will resonate at $171.5 , \text{Hz}$ (roughly an F3 note).

Frequently Asked Questions

A clarinet acts as a pipe closed at one end (by the reed/mouth). Because the standing wave must have a node at the closed end and an antinode at the open end, only waves that fit $1/4$, $3/4$, $5/4$, etc., of a wavelength will resonate. The even harmonics ($2/4$, $4/4$) cannot physically form.

The speed of sound ($v$) changes with air temperature; sound travels faster in hot air. According to the formula, if velocity increases while the pipe length stays the same, the resonant frequency increases (the instrument goes sharp).

Yes, through acoustic resonance. If a singer produces a loud, sustained note that exactly matches the natural resonant frequency of the wine glass, the glass absorbs the acoustic energy. The vibrations build up until the glass shatters.