Construction, DIY & Materials

Voltage Drop Calculator

Calculate the voltage drop percentage and select the correct wire size (AWG) for single-phase or three-phase runs to meet NEC limits.

A
ft
CM
V
Voltage Drop (%)
6.585

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The Physics of Resistance

When electricity flows through a copper wire, it is not a perfect, frictionless highway. The copper metal itself resists the flow of electrons. This resistance creates heat, and more importantly, it causes the electrical "pressure" (Voltage) to slowly drop as the electricity travels further down the wire.

This phenomenon is called Voltage Drop.

If you are wiring a light switch 10 feet away from the breaker panel, voltage drop is negligible. However, if you are burying a massive 300-foot underground cable to power a detached garage or a remote well pump, voltage drop becomes the most critical mathematical factor in the entire electrical design.

If a 120-Volt appliance (like a heavy-duty air compressor) is located 300 feet away, the wire resistance might cause the voltage to drop to 105 Volts by the time it reaches the motor. Running an electric motor on "low voltage" causes it to draw excessive amperage, overheat violently, and permanently burn out the motor coils in a matter of minutes.

The National Electrical Code (NEC) Standard

To prevent appliances from burning out and wires from overheating, the National Electrical Code (NEC) highly recommends strict limits on allowable voltage drop:

  • Branch Circuits: Maximum of 3% voltage drop from the breaker panel to the final outlet.
  • Total System: Maximum of 5% voltage drop from the main utility meter all the way to the final outlet.

If your calculated voltage drop exceeds 3%, you cannot use standard-sized wire. You must "Upsize" the wire (e.g., jump from a 12-gauge wire to a much thicker 10-gauge wire). A thicker wire has more physical copper, which reduces the friction, allowing the electricity to travel the long distance without losing its voltage pressure.

How to Calculate Voltage Drop

Calculating single-phase AC voltage drop requires four distinct variables: the length of the run, the amperage load, the physical cross-sectional area of the wire, and a constant value representing the electrical resistance of copper.

The Variables

  1. Length (L): The one-way distance of the wire run in feet.
  2. Current (I): The maximum Amperage the appliance will draw (e.g., 20 Amps).
  3. Constant (K): The specific resistivity of the metal. For standard Copper wire, this is universally accepted as 12.9 ohms-cmil/ft. (For Aluminum wire, it is 21.2).
  4. Circular Mils (CM): The exact cross-sectional area of the wire. You must look this up on an AWG chart. (e.g., 12 AWG wire = 6,530 CM; 10 AWG wire = 10,380 CM).

The Formula

The universal engineering formula for single-phase voltage drop is:

Voltage Drop = (2 × K × I × L) ÷ CM

Where:
Voltage Drop=
Input value
CM=
Wire Area (CM)

(Note: We multiply by 2 because the electricity has to travel down the hot wire to the appliance, and then travel all the way back along the neutral wire to complete the circuit).

Once you calculate the absolute raw voltage drop, you divide it by the starting System Voltage (e.g., 120V) to find the Percentage of Drop.

Example Calculation

You want to run a heavy 20 Amp power saw at the end of your driveway, which is 100 feet away from the 120V breaker panel. You plan to use standard 12 AWG copper wire (which has an area of 6,530 CM).

  1. Constant: 2 × 12.9 = 25.8
  2. Multiply by Amps and Length: 25.8 × 20 Amps × 100 feet = 51,600
  3. Divide by Circular Mils: 51,600 ÷ 6,530 = 7.9 Volts dropped
  4. Calculate Percentage: 7.9V ÷ 120V = 6.58% Voltage Drop

Result: A 6.58% drop violently violates the 3% NEC limit. The voltage reaching the saw will only be 112 Volts, and the saw will likely overheat.

The Fix: You must upsize the wire to thick 8 AWG (16,510 CM). Doing the math again (51,600 ÷ 16,510) yields a drop of only 3.1 Volts, or 2.5%, which is perfectly safe.

Frequently Asked Questions

Yes, drastically less! This is the primary reason the utility company transmits power across the city at massive 10,000+ voltages. Higher voltage allows you to push the exact same amount of total power (Watts) using half the Amperage. Because Amperage causes the friction/resistance in the wire, doubling the voltage to 240V effectively cuts your percentage of voltage drop in half, allowing you to run wires much farther.

When you turn on a vacuum cleaner with a massive electric motor, it causes an instantaneous 'Inrush Current'—a massive spike in Amperage just to get the heavy motor spinning. This momentary spike in Amperage causes a severe, instantaneous voltage drop across the entire circuit. The voltage drops below 120V for a fraction of a second, which causes the incandescent lightbulbs on that same circuit to visually dim.

Yes. Aluminum is a significantly worse conductor of electricity than pure copper; it has a higher internal resistance (a 'K' constant of 21.2 compared to copper's 12.9). If you use aluminum wire, the voltage drop will be drastically higher. To compensate, if a job requires a 10 AWG copper wire, you must upsize to an even thicker 8 AWG aluminum wire to achieve the exact same performance.