Physics & Mechanics

Combined Gas Law Calculator

Calculate pressure, volume, or temperature using the Combined Gas Law. Solves states for fixed amounts of ideal gases.

Pa
L
K
Pa
K
Final Volume (V₂)
6.667

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The Ultimate Gas Law

The Combined Gas Law does exactly what its name implies: it elegantly combines Boyle's Law, Charles's Law, and Gay-Lussac's Law into one master equation. It establishes the relationship between pressure, volume, and temperature for a fixed amount (moles) of gas.

While the individual laws (Boyle's, Charles's, Gay-Lussac's) require one variable to be held perfectly constant, the real world is rarely that perfectly controlled. The Combined Gas Law allows you to calculate the final state of a gas when all three variables—pressure, volume, and temperature—are actively changing at the exact same time.

Practical Engineering

  • Weather Balloons: As a meteorological weather balloon ascends into the stratosphere, the atmospheric pressure severely drops (causing expansion), but the temperature also severely drops (causing contraction). The Combined Gas Law allows meteorologists to accurately predict the final volume of the balloon and at what altitude it will ultimately burst.
  • Internal Combustion Engines: Inside a car engine cylinder, a mixture of fuel and air is violently compressed (decreasing volume, increasing pressure), and then ignited (massive spike in temperature, causing a massive spike in pressure). This law perfectly describes that chaotic cycle.
  • HVAC Systems: Air conditioners and refrigerators rely on compressors and expansion valves that constantly change the pressure, volume, and temperature of refrigerant gases to move heat out of your home.

The Formula

P1V1T1=P2V2T2\begin{aligned} \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \end{aligned}

Where:
P1,V1,T1P_1, V_1, T_1=
Initial Pressure, Volume, and Absolute Temperature
P2,V2,T2P_2, V_2, T_2=
Final Pressure, Volume, and Absolute Temperature

Example Calculation

A weather balloon is filled with $10,000 , \text{Liters}$ of helium at sea level, where the pressure is $100,000 , \text{Pa}$ and the temperature is $300 , \text{K}$ (about $27^\circ\text{C}$). It ascends to an altitude where the pressure has dropped to $10,000 , \text{Pa}$ and the temperature has plummeted to $210 , \text{K}$.

  1. Calculate Initial State ($P_1 \cdot V_1 / T_1$): $(100,000 \cdot 10,000) / 300 = 3,333,333.33$.
  2. Multiply by Final Temperature ($T_2$): $3,333,333.33 \cdot 210 = 700,000,000$.
  3. Divide by Final Pressure ($P_2$): $700,000,000 / 10,000 = 70,000 , \text{Liters}$.

Despite the freezing cold temperature attempting to shrink the balloon, the massive drop in external atmospheric pressure wins out, and the balloon expands to $70,000 , \text{Liters}$.

Frequently Asked Questions

The Ideal Gas Law ($PV=nRT$) is used to find a single unknown variable in a static state when you know the number of moles. The Combined Gas Law is used to find a new variable when a gas undergoes a dynamic change from State 1 to State 2, assuming no gas escapes the container.

If the temperature doesn't change ($T_1 = T_2$), they simply cancel out of the equation on both sides, and the Combined Gas Law perfectly collapses back into Boyle's Law ($P_1V_1 = P_2V_2$).

No! Just like Charles's and Gay-Lussac's laws, any gas law involving temperature requires Absolute Temperature (Kelvin). Using Celsius or Fahrenheit will result in catastrophic mathematical errors, especially around freezing temperatures.