Physics & Mechanics

Heat Transfer Calculator

Calculate the rate of conductive heat transfer through a material based on its thermal conductivity, area, thickness, and temperature difference.

W/(m·K)
K
m
Heat Transfer Rate (P)
15,400

Calculated locally in your browser. Fast, secure, and private.

Conduction of Thermal Energy

Heat naturally flows from hot objects to cold objects. This calculator specifically measures Conduction, which is the transfer of heat through a solid material via direct microscopic collisions of particles and movement of electrons within a body.

Fourier's Law of Heat Conduction states that the rate of heat transfer (the Power, measured in Watts) through a material is directly proportional to the temperature difference and the cross-sectional area, but inversely proportional to the thickness of the material.

Thermal Insulation and Heat Sinks

  • Home Insulation: The walls of your house are filled with fiberglass or foam. These materials have a terrible thermal conductivity ($k$). Furthermore, the walls are thick ($d$). According to the formula, minimizing $k$ and maximizing $d$ brutally chokes the flow of heat, keeping your house warm in the winter and cool in the summer.
  • Computer Processors: A CPU generates a massive amount of heat in a tiny area. Engineers use Copper or Aluminum because they have an incredibly high thermal conductivity ($k$). The heatsink is designed with hundreds of thin fins to absolutely maximize the surface area ($A$), ensuring the heat transfers out of the metal and into the air as fast as possible.
  • Double-Pane Windows: Glass conducts heat relatively well. By putting two panes of glass together with a thick layer of trapped Argon gas between them (Argon has a terrible thermal conductivity), window manufacturers can drastically slash the heat transfer out of your home.

The Formula

P=kAΔTd\begin{aligned} P = \frac{k \cdot A \cdot \Delta T}{d} \end{aligned}

Where:
P=
Rate of Heat Transfer / Power (Watts, W)
k=
Thermal Conductivity of the material (W/(m·K))
A=
Cross-Sectional Area (m²)
ΔT\Delta T=
Temperature Difference across the material (K)
d=
Thickness of the material (m)

Example Calculation

You have a solid copper plate that is $0.1 , \text{m}^2$ in area and $0.02 , \text{meters}$ thick. One side is touching boiling water ($100^\circ\text{C}$), the other side is touching ice water ($0^\circ\text{C}$), making $\Delta T = 100 , \text{K}$. The thermal conductivity of copper is $385 , \text{W/(m}\cdot\text{K)}$.

  1. Multiply $k \cdot A \cdot \Delta T$: $385 \cdot 0.1 \cdot 100 = 3,850$.
  2. Divide by thickness ($d$): $3,850 / 0.02 = 192,500 , \text{Watts}$.

An absolutely staggering $192,500 , \text{Joules}$ of thermal energy is blasting through that copper plate every single second.

Frequently Asked Questions

Conduction is transfer through solids. Convection is the transfer of heat by the physical movement of fluids (like hot air rising or boiling water rolling). Radiation is the transfer of heat via electromagnetic waves (like feeling the heat of the sun on your face through the vacuum of space).

Because metal has a massively higher thermal conductivity ($k$) than wood. When you touch a metal desk, it conducts the heat out of your warm hand and into the metal extremely fast, triggering the 'cold' receptors in your skin. Wood acts as an insulator and doesn't steal your body heat.

No. Conduction requires the physical collision of atoms to pass the kinetic energy along. A perfect vacuum has no atoms, making its thermal conductivity exactly zero. This is why vacuum-insulated Thermos flasks keep coffee hot for 24 hours.