Physics & Mechanics

Orbital Velocity Calculator

Calculate the orbital velocity required to keep a satellite in orbit at a given altitude around a planet or celestial body.

×10²⁴ kg
km
km
Orbital Velocity
7,672.49
Orbital Velocity (km/s)7.672 km/s

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The Physics of Orbiting

When you look up at the International Space Station or the moon, they appear to be floating weightlessly. In reality, they are in the grip of Earth's immense gravity and are falling toward the ground at thousands of miles per hour.

So why don't they crash? Because they are moving sideways incredibly fast. Orbital velocity is the precise horizontal speed an object needs so that as it falls toward the planet, the curvature of the planet drops away beneath it at the exact same rate. The object is in a perpetual state of falling but constantly missing the ground.

Calculating the Sweet Spot

Orbital velocity relies on a delicate balance. If a satellite moves too slowly, gravity pulls it down into the atmosphere where it burns up. If it moves too fast, its momentum overcomes gravity and it slingshots out into deep space.

To maintain a stable circular orbit, the gravitational pull of the planet must act perfectly as the centripetal force holding the satellite in its circular path.

The Formula

By setting Newton's law of universal gravitation equal to the centripetal force equation, we can derive the precise speed required for an orbit at any altitude:

v=GMr\begin{aligned} v = \sqrt{\frac{GM}{r}} \end{aligned}

Where:
v=
Orbital Velocity
G=
Universal Gravitational Constant
M=
Mass of the central body
r=
Distance from the center of mass

Where:

  • $G$ is the universal gravitational constant ($6.67430 \times 10^{-11} , \text{N}\cdot\text{m}^2/\text{kg}^2$).
  • $M$ is the mass of the central planet.
  • $r$ is the total distance from the center of the planet to the satellite (Planet Radius + Orbital Altitude).

Example: The International Space Station

The ISS orbits Earth at an altitude of approximately $400 , \text{km}$. Let's find its speed.

  1. Earth's Mass ($M$): $5.972 \times 10^{24} , \text{kg}$
  2. Total Radius ($r$): Earth's radius ($6,371 , \text{km}$) + Altitude ($400 , \text{km}$) = $6,771 , \text{km}$ (or $6,771,000 , \text{meters}$).
  3. The Calculation: $v = \sqrt{\frac{(6.67430 \times 10^{-11}) \cdot (5.972 \times 10^{24})}{6771000}}$
  4. The Result: The ISS must travel at exactly $7,672 , \text{m/s}$ (roughly $17,100 , \text{mph}$) to avoid falling out of the sky. At this speed, it circles the entire globe once every 90 minutes.

Frequently Asked Questions

No. Just like escape velocity, the mass of the orbiting object mathematically cancels out of the equation. A tiny 1kg cubesat and the massive 420,000kg International Space Station both must travel at the exact same speed (17,100 mph) to maintain an orbit at 400km altitude.

A geostationary orbit is a special altitude (roughly 35,786 km above Earth's equator) where the required orbital velocity matches the rotational speed of the Earth perfectly. A satellite at this altitude takes exactly 24 hours to orbit, meaning it appears to hover perfectly still over the same spot on the ground.

As you move further away from the planet, the strength of gravity weakens. Because gravity is the invisible 'string' holding the satellite in a circle, a weaker pull means you need less sideways speed to avoid being pulled down. Therefore, high-altitude satellites travel much slower than low-altitude satellites.