Physics & Mechanics

Poiseuille's Law Calculator

Calculate volumetric flow rate of laminar flow through a cylindrical pipe based on pressure drop, radius, length, and fluid viscosity.

Pa
m
m
Pa·s
Volumetric Flow Rate
0.123

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Laminar Flow in Tubes

Poiseuille's law (also known as the Hagen-Poiseuille equation) describes the pressure drop in an incompressible and Newtonian fluid undergoing completely laminar flow through a long cylindrical pipe of constant cross-section.

Unlike Bernoulli's equation, which assumes a perfect frictionless fluid, Poiseuille's law accounts for the viscous friction between the fluid and the pipe walls. It reveals a profound relationship: the volumetric flow rate is directly proportional to the fourth power of the pipe's radius ($r^4$). This means that even a tiny change in a pipe's diameter results in a massive change in fluid flow.

Applications in Medicine and Engineering

  • Blood Flow: The human cardiovascular system relies on this law. If plaque buildup decreases the radius of an artery by just 10%, the flow rate drops by over 34%, forcing the heart to pump dangerously harder to maintain blood pressure.
  • Oil Pipelines: Heavy crude oil is highly viscous. Engineers use Poiseuille's law to determine exactly how powerful the pumping stations must be to push the thick oil across hundreds of miles of pipeline.
  • Needles and Syringes: The gauge (radius) of an IV needle determines how quickly fluids can be injected. A slightly wider needle allows a drastically faster injection rate.

The Formula

Q=πΔPr48μL\begin{aligned} Q = \frac{\pi \cdot \Delta P \cdot r^4}{8 \cdot \mu \cdot L} \end{aligned}

Where:
Q=
Volumetric Flow Rate (m³/s)
ΔP\Delta P=
Pressure difference across the pipe (Pa)
r=
Internal radius of the pipe (meters)
μ\mu=
Dynamic viscosity of the fluid (Pa·s)
L=
Length of the pipe (meters)

Example Calculation

Calculate the flow rate of water (viscosity $\mu = 0.001 , ext{Pa}\cdot\text{s}$) flowing through a $10 , ext{m}$ garden hose with a radius of $0.01 , ext{m}$ (1 cm) under a pressure difference of $10,000 , ext{Pa}$.

  1. Numerator: $\pi \cdot 10000 \cdot (0.01)^4 = \pi \cdot 10000 \cdot 0.00000001 = 0.000314$.
  2. Denominator: $8 \cdot 0.001 \cdot 10 = 0.08$.
  3. Divide: $0.000314 / 0.08 \approx 0.0039 , ext{m}^3\text{/s}$.

The hose delivers about $3.9$ liters of water every second.

Frequently Asked Questions

No. Poiseuille's law only works for perfectly smooth 'laminar' flow, which usually only occurs at low velocities or in very narrow tubes. Once the fluid starts tumbling and swirling (turbulent flow), friction increases exponentially, and empirical models like the Darcy-Weisbach equation must be used.

Because of the no-slip condition. Fluid molecules touching the pipe wall are completely stationary due to friction, while molecules in the absolute dead center move the fastest. This creates a parabolic velocity profile. Integrating this paraboloid over the circular area mathematically yields $r^4$.

Because of the $r^4$ relationship, if you double the pipe's radius ($2^4 = 16$), the volumetric flow rate increases by a staggering factor of 16, assuming the pressure difference remains constant!